What is the integral of 18x^2-14x+9 ?

The integral of 18x^2-14x+9 is 6x^3-7x^2+9x+C

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integral of 18x^2-14x+9

\int 18 x^{2} - 14 x + 9 d x

6 x^{3} - 7 x^{2} + 9 x + C

Solution steps

\int 18 x^{2} - 14 x + 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 18 x^{2} d x - \int 14 x d x + \int 9 d x

\int 18 x^{2} d x = 6 x^{3}

\int 14 x d x = 7 x^{2}

\int 9 d x = 9 x

= 6 x^{3} - 7 x^{2} + 9 x

Add a constant to the solution

= 6 x^{3} - 7 x^{2} + 9 x + C

x + \frac{2}{x}

t^{2} y^{^{''}} - 2 t y^{^{'}} + 2 y = 3 t^{2}

\int_{1}^{3} arctan (\frac{1}{x}) d x

y = \frac{x ^{2}}{x + 2}, (2, 1)

What is the integral of 18x^2-14x+9 ?
The integral of 18x^2-14x+9 is 6x^3-7x^2+9x+C