What is the derivative of x-2x^2+1 ?

The derivative of x-2x^2+1 is -4x+1

What is the first derivative of x-2x^2+1 ?

The first derivative of x-2x^2+1 is -4x+1

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\frac{d}{d x} (x - 2 x^{2} + 1)

- 4 x + 1

Solution steps

\frac{d}{d x} (x - 2 x^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (1) = 0

= 1 - 4 x + 0

Simplify

= - 4 x + 1

x \to - 2 lim (\frac{( x ^{2} - 3 x - 10 )}{( x ^{2} + 5 x + 6 )})

\frac{d}{d x} (2 (6 x^{2} - 7 x) (12 x - 7))

\int e^{- s x} (2 - x) d x

x \to 1 lim (\frac{1}{x ^{3} - 1})

\frac{d}{d x} (3 - 3 cos (x))

What is the derivative of x-2x^2+1 ?
The derivative of x-2x^2+1 is -4x+1
What is the first derivative of x-2x^2+1 ?
The first derivative of x-2x^2+1 is -4x+1