What is the derivative of arccos(4x) ?

The derivative of arccos(4x) is -4/(sqrt(1-16x^2))

What is the first derivative of arccos(4x) ?

The first derivative of arccos(4x) is -4/(sqrt(1-16x^2))

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\frac{d}{d x} (arccos (4 x))

- \frac{4}{1 - 16 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (4 x))

Apply the chain rule:

- \frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

= - \frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= - \frac{1}{1 - ( 4 x ) ^{2}} \cdot 4

Simplify

- \frac{1}{1 - ( 4 x ) ^{2}} \cdot 4 : - \frac{4}{1 - 16 x ^{2}}

= - \frac{4}{1 - 16 x ^{2}}

\frac{\partial}{\partial y} (ln ∣ x + y ∣)

\frac{d y}{d x} = e^{3 y + 10 x}

\frac{d}{d x} (sin (x) (1 - cos (x)))

n = 0 \sum \infty \frac{1}{2 - e ^{- n}}

f (x) = - 10 x sin (5 x^{2} + 5)

What is the derivative of arccos(4x) ?
The derivative of arccos(4x) is -4/(sqrt(1-16x^2))
What is the first derivative of arccos(4x) ?
The first derivative of arccos(4x) is -4/(sqrt(1-16x^2))