What is the derivative of y=ln(sqrt(x+4)) ?

The derivative of y=ln(sqrt(x+4)) is 1/(2(x+4))

What is the first derivative of y=ln(sqrt(x+4)) ?

The first derivative of y=ln(sqrt(x+4)) is 1/(2(x+4))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = ln (x + 4)

\frac{1}{2 ( x + 4 )}

Solution steps

\frac{d}{d x} (ln (x + 4))

Apply the chain rule:

\frac{1}{x + 4} \frac{d}{d x} (x + 4)

= \frac{1}{x + 4} \frac{d}{d x} (x + 4)

\frac{d}{d x} (x + 4) = \frac{1}{2 x + 4}

= \frac{1}{x + 4} \cdot \frac{1}{2 x + 4}

Simplify

\frac{1}{x + 4} \cdot \frac{1}{2 x + 4} : \frac{1}{2 ( x + 4 )}

= \frac{1}{2 ( x + 4 )}

x \to 0 lim (∣ e^{x} - 1 ∣)

\int 1 + 9 x d x

x y^{^{''}} + 2 y^{^{'}} = 16 x^{2}

\int_{0}^{N} e^{(- s t)} e^{- 5 t} d t

2000 + 530 (ln (x))

What is the derivative of y=ln(sqrt(x+4)) ?
The derivative of y=ln(sqrt(x+4)) is 1/(2(x+4))
What is the first derivative of y=ln(sqrt(x+4)) ?
The first derivative of y=ln(sqrt(x+4)) is 1/(2(x+4))