What is the integral of (18)/(sqrt(1-x^2)) ?

The integral of (18)/(sqrt(1-x^2)) is 18arcsin(x)+C

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integral of (18)/(sqrt(1-x^2))

\int \frac{18}{1 - x ^{2}} d x

18 arcsin (x) + C

Solution steps

\int \frac{18}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 18 arcsin (x)

Add a constant to the solution

= 18 arcsin (x) + C

\int \frac{cos ^{3} ( 3 x )}{sin ^{5} ( 3 x )} d x

\int - \frac{1}{2 - x} d x

f (x) = cot^{5} (x)

(x^{2} - y^{2}) d x + x y d y = 0

\int_{7}^{13} \frac{y}{y ^{2} - 3 y - 4} d y

What is the integral of (18)/(sqrt(1-x^2)) ?
The integral of (18)/(sqrt(1-x^2)) is 18arcsin(x)+C