What is the integral of x/(sqrt(4-5x^2)) ?

The integral of x/(sqrt(4-5x^2)) is -1/5 sqrt(4-5x^2)+C

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integral of x/(sqrt(4-5x^2))

\int \frac{x}{4 - 5 x ^{2}} d x

- \frac{1}{5} 4 - 5 x^{2} + C

Solution steps

\int \frac{x}{4 - 5 x ^{2}} d x

Apply u-substitution

: \int - \frac{1}{10 u} d u

= \int - \frac{1}{10 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{10} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= - \frac{1}{10} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = 4 - 5 x^{2}

= - \frac{1}{10} \cdot 2 (4 - 5 x^{2})^{\frac{1}{2}}

Simplify

- \frac{1}{10} \cdot 2 (4 - 5 x^{2})^{\frac{1}{2}} : - \frac{1}{5} 4 - 5 x^{2}

= - \frac{1}{5} 4 - 5 x^{2}

Add a constant to the solution

= - \frac{1}{5} 4 - 5 x^{2} + C

f (x) = \frac{x}{x + 5}

6 cos (x)

y^{^{''}} + 16 y = - 32 sec (4 t)

\int 3 y^{2} - 2 x d y

\frac{d}{d x} (ln (ln (2 x^{4})))

What is the integral of x/(sqrt(4-5x^2)) ?
The integral of x/(sqrt(4-5x^2)) is -1/5 sqrt(4-5x^2)+C