What is the derivative of sqrt(1.8x+2.5) ?

The derivative of sqrt(1.8x+2.5) is (0.9)/(sqrt(1.8x+2.5))

What is the first derivative of sqrt(1.8x+2.5) ?

The first derivative of sqrt(1.8x+2.5) is (0.9)/(sqrt(1.8x+2.5))

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\frac{d}{d x} (1.8 x + 2.5)

\frac{0.9}{1.8 x + 2.5}

Solution steps

\frac{d}{d x} (1.8 x + 2.5)

Apply the chain rule:

\frac{1}{2 1.8 x + 2.5} \frac{d}{d x} (1.8 x + 2.5)

= \frac{1}{2 1.8 x + 2.5} \frac{d}{d x} (1.8 x + 2.5)

\frac{d}{d x} (1.8 x + 2.5) = 1.8

= \frac{1}{2 1.8 x + 2.5} \cdot 1.8

Simplify

\frac{1}{2 1.8 x + 2.5} \cdot 1.8 : \frac{0.9}{1.8 x + 2.5}

= \frac{0.9}{1.8 x + 2.5}

\int \frac{5 x + 1}{( 2 x + 1 ) ( x - 1 )} d x

\int \frac{x ^{3}}{( x ^{2} + 1 ) ^{3}} d x

\int \frac{1}{1 - z ^{2}} d z

x \to 1 + lim (e^{l n (l n (x))})

e^{- y}

What is the derivative of sqrt(1.8x+2.5) ?
The derivative of sqrt(1.8x+2.5) is (0.9)/(sqrt(1.8x+2.5))
What is the first derivative of sqrt(1.8x+2.5) ?
The first derivative of sqrt(1.8x+2.5) is (0.9)/(sqrt(1.8x+2.5))