What is the integral of (5x+1)/((2x+1)(x-1)) ?

The integral of (5x+1)/((2x+1)(x-1)) is 1/2 ln|2x+1|+2ln|x-1|+C

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integral of (5x+1)/((2x+1)(x-1))

\int \frac{5 x + 1}{( 2 x + 1 ) ( x - 1 )} d x

\frac{1}{2} ln ∣ 2 x + 1 ∣ + 2 ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{5 x + 1}{( 2 x + 1 ) ( x - 1 )} d x

Take the partial fraction of

\frac{5 x + 1}{( 2 x + 1 ) ( x - 1 )} : \frac{1}{2 x + 1} + \frac{2}{x - 1}

= \int \frac{1}{2 x + 1} + \frac{2}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{2 x + 1} d x + \int \frac{2}{x - 1} d x

\int \frac{1}{2 x + 1} d x = \frac{1}{2} ln ∣ 2 x + 1 ∣

\int \frac{2}{x - 1} d x = 2 ln ∣ x - 1 ∣

= \frac{1}{2} ln ∣ 2 x + 1 ∣ + 2 ln ∣ x - 1 ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ 2 x + 1 ∣ + 2 ln ∣ x - 1 ∣ + C

\int \frac{x ^{3}}{( x ^{2} + 1 ) ^{3}} d x

\int \frac{1}{1 - z ^{2}} d z

x \to 1 + lim (e^{l n (l n (x))})

e^{- y}

\int_{1}^{5} \frac{6}{x ^{2}} d x

What is the integral of (5x+1)/((2x+1)(x-1)) ?
The integral of (5x+1)/((2x+1)(x-1)) is 1/2 ln|2x+1|+2ln|x-1|+C