What is (\partial)/(\partial x)(-2cos(-3x+7)) ?

The answer to (\partial)/(\partial x)(-2cos(-3x+7)) is -6sin(-3x+7)

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(\partial)/(\partial x)(-2cos(-3x+7))

\frac{\partial}{\partial x} (- 2 cos (- 3 x + 7))

- 6 sin (- 3 x + 7)

Solution steps

\frac{\partial}{\partial x} (- 2 cos (- 3 x + 7))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{\partial}{\partial x} (cos (- 3 x + 7))

Apply the chain rule:

- sin (- 3 x + 7) \frac{\partial}{\partial x} (- 3 x + 7)

= - sin (- 3 x + 7) \frac{\partial}{\partial x} (- 3 x + 7)

\frac{\partial}{\partial x} (- 3 x + 7) = - 3

= - 2 (- sin (- 3 x + 7) (- 3))

Simplify

= - 6 sin (- 3 x + 7)

\frac{d}{d t} (2 t^{- 1})

f (x) = 2 e x

(1 + \frac{1}{x}) \frac{d y}{d x} + y = 0

x \to 0 - lim (\frac{tan ( x )}{x})

\int e^{x} (π + e^{x}) d x

What is (\partial)/(\partial x)(-2cos(-3x+7)) ?
The answer to (\partial)/(\partial x)(-2cos(-3x+7)) is -6sin(-3x+7)