What is the solution for (1+1/x)(dy)/(dx)+y=0 ?

The solution for (1+1/x)(dy)/(dx)+y=0 is y=e^{-x-1+c_{1}}x+e^{-x-1+c_{1}}

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(1+1/x)(dy)/(dx)+y=0

(1 + \frac{1}{x}) \frac{d y}{d x} + y = 0

y = e^{- x - 1 + c_{1}} x + e^{- x - 1 + c_{1}}

Solution steps

(1 + \frac{1}{x}) \frac{d y}{d x} + y = 0

Solve separable ODE:

y = e^{- x - 1 + c_{1}} x + e^{- x - 1 + c_{1}}

y = e^{- x - 1 + c_{1}} x + e^{- x - 1 + c_{1}}

x \to 0 - lim (\frac{tan ( x )}{x})

\int e^{x} (π + e^{x}) d x

\frac{d x}{d t} = 2 x + t

\frac{1}{s ^{4}}

x^{^{''}} = - k^{2} x

What is the solution for (1+1/x)(dy)/(dx)+y=0 ?
The solution for (1+1/x)(dy)/(dx)+y=0 is y=e^{-x-1+c_{1}}x+e^{-x-1+c_{1}}