What is (\partial)/(\partial y)(y^{2/3}) ?

The answer to (\partial)/(\partial y)(y^{2/3}) is 2/(3y^{1/3)}

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(\partial)/(\partial y)(y^{2/3})

\frac{\partial}{\partial y} (y^{\frac{2}{3}})

\frac{2}{3 y ^{\frac{1}{3}}}

Solution steps

\frac{\partial}{\partial y} (y^{\frac{2}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} y^{\frac{2}{3} - 1}

Simplify

\frac{2}{3} y^{\frac{2}{3} - 1} : \frac{2}{3 y ^{\frac{1}{3}}}

= \frac{2}{3 y ^{\frac{1}{3}}}

\frac{d}{d x} (ln (6 x^{2}))

t y^{^{'}} + 3 y = 0

\frac{\partial}{\partial y} (z ln (y) + e^{2})

\frac{d}{d x} (- x e^{\frac{y}{x}})

\int_{0}^{\frac{π}{2}} cot (x) d x

What is (\partial)/(\partial y)(y^{2/3}) ?
The answer to (\partial)/(\partial y)(y^{2/3}) is 2/(3y^{1/3)}