What is the tangent of y=x^3-3x+2,(2,4) ?

The tangent of y=x^3-3x+2,(2,4) is y=9x-14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^3-3x+2,(2,4)

tangent of

y = x^{3} - 3 x + 2, (2, 4)

y = 9 x - 14

Solution steps

Find the slope of

y = x^{3} - 3 x + 2 : \frac{d y}{d x} = 3 x^{2} - 3

Compute the slope of

y = x^{3} - 3 x + 2

(2, 4) : m = 9

Find the line with slope m=

9

and passing through

(2, 4) : y = 9 x - 14

y = 9 x - 14

\int_{- \infty}^{- 1} e^{- 2 x} d x

\int \frac{3 x ^{3} - 3 x ^{2} + 1}{x ^{2} - x} d x

\int x arcsin (d) x d x

\frac{d}{d x} (- 7 ln (3 x + 4))

\int x (x^{2} + 3)^{4} d x

What is the tangent of y=x^3-3x+2,(2,4) ?
The tangent of y=x^3-3x+2,(2,4) is y=9x-14