What is the integral of (x^2)/(sqrt(3+1)) ?

The integral of (x^2)/(sqrt(3+1)) is (x^3)/6+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^2)/(sqrt(3+1))

\int \frac{x ^{2}}{3 + 1} d x

\frac{x ^{3}}{6} + C

Solution steps

\int \frac{x ^{2}}{3 + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3 + 1} \cdot \int x^{2} d x

\frac{1}{3 + 1} = \frac{1}{2}

= \frac{1}{2} \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= \frac{1}{2} \cdot \frac{x ^{3}}{3}

Simplify

\frac{1}{2} \cdot \frac{x ^{3}}{3} : \frac{x ^{3}}{6}

= \frac{x ^{3}}{6}

Add a constant to the solution

= \frac{x ^{3}}{6} + C

f (x) = sin (sin (x)), (3 π, 0)

f (x) = 1000 - x - \frac{1}{8} x^{2}

f (x) = x - 3

y^{^{''}} + 4 y^{^{'}} + 8 y = 325 e^{2 t} cos (5 t)

\int 2 y x d x

What is the integral of (x^2)/(sqrt(3+1)) ?
The integral of (x^2)/(sqrt(3+1)) is (x^3)/6+C