What is the integral from 1 to 4 of (4x^2) ?

The integral from 1 to 4 of (4x^2) is 84

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integral from 1 to 4 of (4x^2)

\int_{1}^{4} (4 x^{2}) d x

84

Solution steps

\int_{1}^{4} 4 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{4}

= 4 [\frac{x ^{3}}{3}]_{1}^{4}

Compute the boundaries:

21

= 4 \cdot 21

Simplify

= 84

x^{2} y^{^{''}} - 5 x y^{^{'}} + 9 y = 0, y (1) = - 5, y^{^{'}} (1) = - 17

(- 3.1) (0.3)

4 arcsin (x)

x \to 0 lim (2 x^{3} + ln (x))

\frac{d}{d x} (\frac{3 3 x ^{2}}{2})

What is the integral from 1 to 4 of (4x^2) ?
The integral from 1 to 4 of (4x^2) is 84