What is area 5cos(7x),5-5cos(7x),[0, pi/7 ] ?

The answer to area 5cos(7x),5-5cos(7x),[0, pi/7 ] is (5pi+30sqrt(3))/(21)

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area 5cos(7x),5-5cos(7x),[0, pi/7 ]

area

5 cos (7 x), 5 - 5 cos (7 x), [0, \frac{π}{7}]

\frac{5 π + 30 3}{21}

Decimal Notation

3.22235 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{7}} ∣ 5 cos (7 x) - (5 - 5 cos (7 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{7}} ∣ 5 cos (7 x) - (5 - 5 cos (7 x)) ∣ d x : \frac{5 π + 30 3}{21}

The area is:

= \frac{5 π + 30 3}{21}

y^{^{'}} + \frac{y}{6.96} = 0.0025862069

\frac{d}{d x} (ln (x^{\frac{1}{5}}))

\int x^{2} + x^{- 2} d x

sin (2 x) d x + cos (6 y) d y = 0

What is area 5cos(7x),5-5cos(7x),[0, pi/7 ] ?
The answer to area 5cos(7x),5-5cos(7x),[0, pi/7 ] is (5pi+30sqrt(3))/(21)