What is the integral of sin(t)-cos(t) ?

The integral of sin(t)-cos(t) is -cos(t)-sin(t)+C

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integral of sin(t)-cos(t)

\int sin (t) - cos (t) d t

- cos (t) - sin (t) + C

Solution steps

\int sin (t) - cos (t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sin (t) d t - \int cos (t) d t

\int sin (t) d t = - cos (t)

\int cos (t) d t = sin (t)

= - cos (t) - sin (t)

Add a constant to the solution

= - cos (t) - sin (t) + C

x \to 2 lim (ln (x - 2))

x \to - 1 lim (30)

\frac{\partial}{\partial x} (3 x^{2} y^{2} - 3)

(2 - x - 3 x^{3}) (7 + x^{5})

(s^{\frac{- 1}{2}} + 7 s) (1 - s^{- 1})

What is the integral of sin(t)-cos(t) ?
The integral of sin(t)-cos(t) is -cos(t)-sin(t)+C