What is the tangent of f(x)=3x-2sqrt(x),\at x=1 ?

The tangent of f(x)=3x-2sqrt(x),\at x=1 is y=2x-1

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tangent of f(x)=3x-2sqrt(x),\at x=1

tangent of

f (x) = 3 x - 2 x, at x = 1

y = 2 x - 1

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = 3 x - 2 x : \frac{df ( x )}{d x} = 3 - \frac{1}{x}

Compute the slope of

f (x) = 3 x - 2 x

x = 1 : m = 2

Find the line with slope m=

2

and passing through

(1, 1) : y = 2 x - 1

y = 2 x - 1

\frac{\partial}{\partial y} (\frac{9 y}{x ^{5}})

y^{^{''}} + 22 y = 0

\frac{\partial}{\partial y} (x^{2} + x y + y^{2})

10 - 7 x, y = 0, x^{2} - 20

\int 2 x + 3 x^{- 2} d x

What is the tangent of f(x)=3x-2sqrt(x),\at x=1 ?
The tangent of f(x)=3x-2sqrt(x),\at x=1 is y=2x-1