What is the derivative of (x^5/(a+b)-(x^2)/(a-b)) ?

The derivative of (x^5/(a+b)-(x^2)/(a-b)) is (5x^4)/(a+b)-(2x)/(a-b)

What is the first derivative of (x^5/(a+b)-(x^2)/(a-b)) ?

The first derivative of (x^5/(a+b)-(x^2)/(a-b)) is (5x^4)/(a+b)-(2x)/(a-b)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{x ^{5}}{a + b} - \frac{x ^{2}}{a - b})

\frac{5 x ^{4}}{a + b} - \frac{2 x}{a - b}

Solution steps

\frac{d}{d x} (\frac{x ^{5}}{a + b} - \frac{x ^{2}}{a - b})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{5}}{a + b}) - \frac{d}{d x} (\frac{x ^{2}}{a - b})

\frac{d}{d x} (\frac{x ^{5}}{a + b}) = \frac{5 x ^{4}}{a + b}

\frac{d}{d x} (\frac{x ^{2}}{a - b}) = \frac{2 x}{a - b}

= \frac{5 x ^{4}}{a + b} - \frac{2 x}{a - b}

\frac{d}{d x} (0.7 x^{2})

\frac{d}{d x} (\frac{1}{- 2 x ^{2}})

n = 0 \sum \infty (2 x)^{n}

f (x) = x 2^{x}

(- 2.3) (2.2)

What is the derivative of (x^5/(a+b)-(x^2)/(a-b)) ?
The derivative of (x^5/(a+b)-(x^2)/(a-b)) is (5x^4)/(a+b)-(2x)/(a-b)
What is the first derivative of (x^5/(a+b)-(x^2)/(a-b)) ?
The first derivative of (x^5/(a+b)-(x^2)/(a-b)) is (5x^4)/(a+b)-(2x)/(a-b)