What is laplacetransform e^{-2t-3} ?

The answer to laplacetransform e^{-2t-3} is 1/(e^3(s+2))

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laplacetransform e^{-2t-3}

laplace transform

e^{- 2 t - 3}

\frac{1}{e ^{3} ( s + 2 )}

Solution steps

L {e^{- 2 t - 3}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{- 3} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{- 3} \frac{1}{s + 2}

Refine

e^{- 3} \frac{1}{s + 2} : \frac{1}{e ^{3} ( s + 2 )}

= \frac{1}{e ^{3} ( s + 2 )}

\frac{d}{d x} (\frac{x}{π})

\frac{d}{d x} (arccos (y - 2 x))

\int sec^{2} (θ) tan^{7} (θ) d θ

x \to 2 lim (\frac{- 1}{( x + 2 )})

\frac{d}{d x} (\frac{2 - x}{1 + 2 x ^{2}})

What is laplacetransform e^{-2t-3} ?
The answer to laplacetransform e^{-2t-3} is 1/(e^3(s+2))