What is the d/(dθ)(cos(θ)-2sin(θ)) ?

The d/(dθ)(cos(θ)-2sin(θ)) is -sin(θ)-2cos(θ)

What is the first d/(dθ)(cos(θ)-2sin(θ)) ?

The first d/(dθ)(cos(θ)-2sin(θ)) is -sin(θ)-2cos(θ)

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\frac{d}{d θ} (cos (θ) - 2 sin (θ))

- sin (θ) - 2 cos (θ)

Solution steps

\frac{d}{d θ} (cos (θ) - 2 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (cos (θ)) - \frac{d}{d θ} (2 sin (θ))

\frac{d}{d θ} (cos (θ)) = - sin (θ)

\frac{d}{d θ} (2 sin (θ)) = 2 cos (θ)

= - sin (θ) - 2 cos (θ)

x \to 0 - lim (a x^{2} + \frac{b}{2})

\frac{2}{x ^{2}}, at (1.2)

\int \frac{1}{x ln ^{4} ( x )} d x

y^{^{'}} = y^{\frac{1}{3}}

\frac{d y}{d x} = 5 x + 15 y

What is the d/(dθ)(cos(θ)-2sin(θ)) ?
The d/(dθ)(cos(θ)-2sin(θ)) is -sin(θ)-2cos(θ)
What is the first d/(dθ)(cos(θ)-2sin(θ)) ?
The first d/(dθ)(cos(θ)-2sin(θ)) is -sin(θ)-2cos(θ)