What is the derivative of-9x^2+4x+5 ?

The derivative of-9x^2+4x+5 is -18x+4

What is the first derivative of-9x^2+4x+5 ?

The first derivative of-9x^2+4x+5 is -18x+4

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\frac{d}{d x} (- 9 x^{2} + 4 x + 5)

- 18 x + 4

Solution steps

\frac{d}{d x} (- 9 x^{2} + 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (9 x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= - 18 x + 4 + 0

Simplify

= - 18 x + 4

\int cot^{4} (x) d x

\frac{d y}{d x} = \frac{y}{x}

\int \frac{1}{( π x - 1 )} d x

\int 4^{l n (x)} d x

\frac{d ^{2} y}{d x ^{2}} + 5 \frac{d y}{d x} + 6 y = 0

What is the derivative of-9x^2+4x+5 ?
The derivative of-9x^2+4x+5 is -18x+4
What is the first derivative of-9x^2+4x+5 ?
The first derivative of-9x^2+4x+5 is -18x+4