What is implicit (dy)/(dx),xy=y^2 ?

The answer to implicit (dy)/(dx),xy=y^2 is (dy)/(dx)=-y/(x-2y)

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implicit (dy)/(dx),xy=y^2

implicit derivative

\frac{d y}{d x}, x y = y^{2}

\frac{d y}{d x} = - \frac{y}{x - 2 y}

Solution steps

x y = y^{2}

Treat

y

y (x)

Differentiate both sides:

y + x \frac{d y}{d x} = 2 y \frac{d y}{d x}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{y}{x - 2 y}

\frac{d y}{d x} = - \frac{y}{x - 2 y}

\int_{- \infty}^{0} \frac{1}{6 - 10 x} d x

∣ 9 x ∣, x^{2} - 10

\int q^{2} cos (7 q) d q

\frac{d y}{d x} = \frac{( y - y ^{3} )}{a ^{2}}, y (0) = b

\frac{\partial}{\partial x} (b x e^{5 x y})

What is implicit (dy)/(dx),xy=y^2 ?
The answer to implicit (dy)/(dx),xy=y^2 is (dy)/(dx)=-y/(x-2y)