What is the derivative of 4x^3-24x^2+36x ?

The derivative of 4x^3-24x^2+36x is 12x^2-48x+36

What is the first derivative of 4x^3-24x^2+36x ?

The first derivative of 4x^3-24x^2+36x is 12x^2-48x+36

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\frac{d}{d x} (4 x^{3} - 24 x^{2} + 36 x)

12 x^{2} - 48 x + 36

Solution steps

\frac{d}{d x} (4 x^{3} - 24 x^{2} + 36 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (24 x^{2}) + \frac{d}{d x} (36 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (24 x^{2}) = 48 x

\frac{d}{d x} (36 x) = 36

= 12 x^{2} - 48 x + 36

\frac{d P}{d t} = 1 P (500 - P)

- sin (3 x)

x \cdot y^{^{'}} + y = \frac{1}{y ^{2}}

\int 2 x 1 + 4 x^{2} d x

\frac{d}{d x} (cos (7^{6 x}))

What is the derivative of 4x^3-24x^2+36x ?
The derivative of 4x^3-24x^2+36x is 12x^2-48x+36
What is the first derivative of 4x^3-24x^2+36x ?
The first derivative of 4x^3-24x^2+36x is 12x^2-48x+36