What is the derivative of-sin(3x) ?

The derivative of-sin(3x) is -cos(3x)*3

What is the first derivative of-sin(3x) ?

The first derivative of-sin(3x) is -cos(3x)*3

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derivative of

- sin (3 x)

- cos (3 x) \cdot 3

Solution steps

\frac{d}{d x} (- sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - cos (3 x) \cdot 3

x \cdot y^{^{'}} + y = \frac{1}{y ^{2}}

\int 2 x 1 + 4 x^{2} d x

\frac{d}{d x} (cos (7^{6 x}))

x^{2} \frac{d y}{d x} + x y = 1

f (x) = 9 - 4 x^{2}

What is the derivative of-sin(3x) ?
The derivative of-sin(3x) is -cos(3x)*3
What is the first derivative of-sin(3x) ?
The first derivative of-sin(3x) is -cos(3x)*3