What is the derivative of f(x)=9-4x^2 ?

The derivative of f(x)=9-4x^2 is -8x

What is the first derivative of f(x)=9-4x^2 ?

The first derivative of f(x)=9-4x^2 is -8x

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derivative of

f (x) = 9 - 4 x^{2}

- 8 x

Solution steps

\frac{d}{d x} (9 - 4 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9) - \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (9) = 0

\frac{d}{d x} (4 x^{2}) = 8 x

= 0 - 8 x

Simplify

= - 8 x

\int sec^{2} (6 x) d x

\int \frac{t}{e ^{t}} d t

\int \frac{x + 3}{x ^{2} - x + 4} d x

y^{^{''}} + 2 y^{^{'}} + y = 4 e - t

1 y^{2} - 7 y^{4} (y + 9 y^{3})

What is the derivative of f(x)=9-4x^2 ?
The derivative of f(x)=9-4x^2 is -8x
What is the first derivative of f(x)=9-4x^2 ?
The first derivative of f(x)=9-4x^2 is -8x