What is the derivative of (x^{12}-1)^3 ?

The derivative of (x^{12}-1)^3 is 36x^{11}(x^{12}-1)^2

What is the first derivative of (x^{12}-1)^3 ?

The first derivative of (x^{12}-1)^3 is 36x^{11}(x^{12}-1)^2

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derivative of

(x^{12} - 1)^{3}

36 x^{11} (x^{12} - 1)^{2}

Solution steps

\frac{d}{d x} ((x^{12} - 1)^{3})

Apply the chain rule:

3 (x^{12} - 1)^{2} \frac{d}{d x} (x^{12} - 1)

= 3 (x^{12} - 1)^{2} \frac{d}{d x} (x^{12} - 1)

\frac{d}{d x} (x^{12} - 1) = 12 x^{11}

= 3 (x^{12} - 1)^{2} \cdot 12 x^{11}

Simplify

= 36 x^{11} (x^{12} - 1)^{2}

\int \frac{7 x ^{3} + x ^{2}}{x} d x

x \to 2 lim (\frac{7 x - 26}{x - 5})

x \to \infty lim (3^{x})

\int 5 sin^{2} (x) cos (x) d x

y^{^{'}} = \frac{y - y ^{2}}{x}

What is the derivative of (x^{12}-1)^3 ?
The derivative of (x^{12}-1)^3 is 36x^{11}(x^{12}-1)^2
What is the first derivative of (x^{12}-1)^3 ?
The first derivative of (x^{12}-1)^3 is 36x^{11}(x^{12}-1)^2