What is the integral of 5sin^2(x)cos(x) ?

The integral of 5sin^2(x)cos(x) is 5/3 sin^3(x)+C

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integral of 5sin^2(x)cos(x)

\int 5 sin^{2} (x) cos (x) d x

\frac{5}{3} sin^{3} (x) + C

Solution steps

\int 5 sin^{2} (x) cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int sin^{2} (x) cos (x) d x

Apply u-substitution

: \int u^{2} d u

= 5 \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= 5 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (x)

= 5 \cdot \frac{sin ^{3} ( x )}{3}

Simplify

5 \cdot \frac{sin ^{3} ( x )}{3} : \frac{5}{3} sin^{3} (x)

= \frac{5}{3} sin^{3} (x)

Add a constant to the solution

= \frac{5}{3} sin^{3} (x) + C

y^{^{'}} = \frac{y - y ^{2}}{x}

x^{\frac{2}{5}}

9 - t

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2} - 3 x}{x + 1})

n = 1 \sum \infty 6 e^{- 5 n}

What is the integral of 5sin^2(x)cos(x) ?
The integral of 5sin^2(x)cos(x) is 5/3 sin^3(x)+C