What is (\partial)/(\partial x)(x^2z^2sin(4y)) ?

The answer to (\partial)/(\partial x)(x^2z^2sin(4y)) is 2xz^2sin(4y)

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(\partial)/(\partial x)(x^2z^2sin(4y))

\frac{\partial}{\partial x} (x^{2} z^{2} sin (4 y))

2 x z^{2} sin (4 y)

Solution steps

\frac{\partial}{\partial x} (x^{2} z^{2} sin (4 y))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z^{2} sin (4 y) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= z^{2} sin (4 y) \cdot 2 x^{2 - 1}

Simplify

= 2 x z^{2} sin (4 y)

\frac{\partial}{\partial y} (\frac{x y}{( x - y )})

x \to 4 lim (\frac{x ^{2} - 5}{x + 5})

f (x) = 3 x^{2} - ln (x), (1, 3)

f (x) = x^{5}, at x = 4

\int (x^{2} + 1) cos (2 x) d x

What is (\partial)/(\partial x)(x^2z^2sin(4y)) ?
The answer to (\partial)/(\partial x)(x^2z^2sin(4y)) is 2xz^2sin(4y)