What is the solution for x(dy)/(dx)=y^2-y,y(1/4)= 1/4 ?

The solution for x(dy)/(dx)=y^2-y,y(1/4)= 1/4 is y= 1/(12x+1)

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x(dy)/(dx)=y^2-y,y(1/4)= 1/4

x \frac{d y}{d x} = y^{2} - y, y (\frac{1}{4}) = \frac{1}{4}

y = \frac{1}{12 x + 1}

Solution steps

x \frac{d y}{d x} = y^{2} - y

Solve Bernoulli ODE:

y = \frac{1}{12 x + 1}

y = \frac{1}{12 x + 1}

x^{2} + a x + b

\frac{\partial}{\partial x} (\frac{e ^{x}}{y + x ^{7}})

4 x^{3} - 18 x^{2} - 48 x

\frac{d}{d x} (4 - 2 x)

2 y = x, \frac{y ^{2}}{2} = x

What is the solution for x(dy)/(dx)=y^2-y,y(1/4)= 1/4 ?
The solution for x(dy)/(dx)=y^2-y,y(1/4)= 1/4 is y= 1/(12x+1)