What is the derivative of (14/(x^3)) ?

The derivative of (14/(x^3)) is -(42)/(x^4)

What is the first derivative of (14/(x^3)) ?

The first derivative of (14/(x^3)) is -(42)/(x^4)

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\frac{d}{d x} (\frac{14}{x ^{3}})

- \frac{42}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{14}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 14 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 14 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 14 (- 3 x^{- 3 - 1})

Simplify

14 (- 3 x^{- 3 - 1}) : - \frac{42}{x ^{4}}

= - \frac{42}{x ^{4}}

\frac{\partial}{\partial x} (x^{\frac{x}{y}} cos (\frac{x}{y}))

n = 1 \sum \infty \frac{1}{( 5 n - 4 ) ^{4}}

\int - 0.4 x^{2} + 1000 d x

\frac{\partial}{\partial x} (ln (\frac{y ^{2}}{x}))

(x - 4)^{3} + 3 x (x - 4)^{2}

What is the derivative of (14/(x^3)) ?
The derivative of (14/(x^3)) is -(42)/(x^4)
What is the first derivative of (14/(x^3)) ?
The first derivative of (14/(x^3)) is -(42)/(x^4)