What is the integral of-0.4x^2+1000 ?

The integral of-0.4x^2+1000 is -0.13333…x^3+1000x+C

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integral of-0.4x^2+1000

\int - 0.4 x^{2} + 1000 d x

- 0.13333 \dots x^{3} + 1000 x + C

Solution steps

\int - 0.4 x^{2} + 1000 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 0.4 x^{2} d x + \int 1000 d x

\int 0.4 x^{2} d x = 0.13333 \dots x^{3}

\int 1000 d x = 1000 x

= - 0.13333 \dots x^{3} + 1000 x

Add a constant to the solution

= - 0.13333 \dots x^{3} + 1000 x + C

\frac{\partial}{\partial x} (ln (\frac{y ^{2}}{x}))

(x - 4)^{3} + 3 x (x - 4)^{2}

x \to - \infty lim (x^{6})

\frac{\partial}{\partial x} (- 4 cos (3 x))

\int \frac{12 s + 12}{( s ^{2} + 1 ) ( s - 1 ) ^{3}} d s

What is the integral of-0.4x^2+1000 ?
The integral of-0.4x^2+1000 is -0.13333…x^3+1000x+C