What is the derivative of-(15x^4/2+(6x^2)/5-x/3-4) ?

The derivative of-(15x^4/2+(6x^2)/5-x/3-4) is -30x^3+(12x)/5-1/3

What is the first derivative of-(15x^4/2+(6x^2)/5-x/3-4) ?

The first derivative of-(15x^4/2+(6x^2)/5-x/3-4) is -30x^3+(12x)/5-1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (- \frac{15 x ^{4}}{2} + \frac{6 x ^{2}}{5} - \frac{x}{3} - 4)

- 30 x^{3} + \frac{12 x}{5} - \frac{1}{3}

Solution steps

\frac{d}{d x} (- \frac{15 x ^{4}}{2} + \frac{6 x ^{2}}{5} - \frac{x}{3} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (\frac{15 x ^{4}}{2}) + \frac{d}{d x} (\frac{6 x ^{2}}{5}) - \frac{d}{d x} (\frac{x}{3}) - \frac{d}{d x} (4)

\frac{d}{d x} (\frac{15 x ^{4}}{2}) = 30 x^{3}

\frac{d}{d x} (\frac{6 x ^{2}}{5}) = \frac{12 x}{5}

\frac{d}{d x} (\frac{x}{3}) = \frac{1}{3}

\frac{d}{d x} (4) = 0

= - 30 x^{3} + \frac{12 x}{5} - \frac{1}{3} - 0

Simplify

= - 30 x^{3} + \frac{12 x}{5} - \frac{1}{3}

\int x cos^{3} (x) d x

x \to 0 lim (\frac{ln ( 1 + \frac{1}{x} )}{x})

\frac{d}{d x} (\frac{x}{( 1 - 2 x ) ^{2}})

\int (cos (x))^{5} sin (x) d x

\int (x^{2} + 2 x)^{5} (2 x + 2) d x

What is the derivative of-(15x^4/2+(6x^2)/5-x/3-4) ?
The derivative of-(15x^4/2+(6x^2)/5-x/3-4) is -30x^3+(12x)/5-1/3
What is the first derivative of-(15x^4/2+(6x^2)/5-x/3-4) ?
The first derivative of-(15x^4/2+(6x^2)/5-x/3-4) is -30x^3+(12x)/5-1/3