What is the derivative of f(x)=x+(49)/x ?

The derivative of f(x)=x+(49)/x is 1-(49)/(x^2)

What is the first derivative of f(x)=x+(49)/x ?

The first derivative of f(x)=x+(49)/x is 1-(49)/(x^2)

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derivative of

f (x) = x + \frac{49}{x}

1 - \frac{49}{x ^{2}}

Solution steps

\frac{d}{d x} (x + \frac{49}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{49}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{49}{x}) = - \frac{49}{x ^{2}}

= 1 - \frac{49}{x ^{2}}

\frac{\partial}{\partial x} (x^{3})

y^{^{'}} + 10 y = 20

n = 1 \sum \infty n + (\frac{7}{8})^{n}

y = x^{3} - x^{2} + x - 1, (1, 0)

\int x^{4} ln^{2} (x) d x

What is the derivative of f(x)=x+(49)/x ?
The derivative of f(x)=x+(49)/x is 1-(49)/(x^2)
What is the first derivative of f(x)=x+(49)/x ?
The first derivative of f(x)=x+(49)/x is 1-(49)/(x^2)