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Popular >

y^'+10y=20

Solution

y^{^{'}} + 10 y = 20

Solution

y = - e^{- 10 t - c_{1}} + 2

Solution steps

y^{'} (t) + 10 y = 20

Solve separable ODE:

y = - e^{- 10 t - c_{1}} + 2

y = - e^{- 10 t - c_{1}} + 2

Popular Examples

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y = x^{3} - x^{2} + x - 1, (1, 0)

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\int x^{4} ln^{2} (x) d x

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\frac{d}{d x} (\frac{4 x}{x + 4})

tangent of y=8+5x^2-2x^3 tangent of

y = 8 + 5 x^{2} - 2 x^{3}

Frequently Asked Questions (FAQ)

What is the solution for y^'+10y=20 ?
The solution for y^'+10y=20 is y=-e^{-10t-c_{1}}+2