What is the derivative of 1/((3+x^2)) ?

The derivative of 1/((3+x^2)) is -2/((3+x)^3)

What is the first derivative of 1/((3+x^2)) ?

The first derivative of 1/((3+x^2)) is -2/((3+x)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{1}{( 3 + x ) ^{2}})

- \frac{2}{( 3 + x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( 3 + x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((3 + x)^{- 2})

Apply the chain rule:

- \frac{2}{( 3 + x ) ^{3}} \frac{d}{d x} (3 + x)

= - \frac{2}{( 3 + x ) ^{3}} \frac{d}{d x} (3 + x)

\frac{d}{d x} (3 + x) = 1

= - \frac{2}{( 3 + x ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( 3 + x ) ^{3}}

\int e^{6 x + 7} d x

\frac{3}{1 + x ^{2}}

x y - π cos (y) = 3 π, (2, π)

\frac{\partial}{\partial t} (\frac{2 r + s}{t})

\frac{d}{d x} (- 12 sin (6 x))

What is the derivative of 1/((3+x^2)) ?
The derivative of 1/((3+x^2)) is -2/((3+x)^3)
What is the first derivative of 1/((3+x^2)) ?
The first derivative of 1/((3+x^2)) is -2/((3+x)^3)