What is the tangent of y=sin(2x),\at x= pi/4 ?

The tangent of y=sin(2x),\at x= pi/4 is y=1

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tangent of y=sin(2x),\at x= pi/4

tangent of

y = sin (2 x), at x = \frac{π}{4}

y = 1

Solution steps

Find the tangent point:

(\frac{π}{4}, 1)

Find the slope of

y = sin (2 x) : \frac{d y}{d x} = cos (2 x) \cdot 2

Compute the slope of

y = sin (2 x)

x = \frac{π}{4} : m = 0

Find the line with slope m=

0

and passing through

(\frac{π}{4}, 1) : y = 1

y = 1

\frac{\partial}{\partial x} (sin (x^{2}))

2 x - 5

\frac{d}{d x} (ln (\frac{1}{x x + 1}))

\frac{d}{d x} (arccos (\frac{1}{x}))

x \to 3 - lim (\frac{6 x}{x - 3})

What is the tangent of y=sin(2x),\at x= pi/4 ?
The tangent of y=sin(2x),\at x= pi/4 is y=1