What is the integral of-(2000)/(x^2) ?

The integral of-(2000)/(x^2) is (2000)/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-(2000)/(x^2)

\int - \frac{2000}{x ^{2}} d x

\frac{2000}{x} + C

Solution steps

\int - \frac{2000}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2000 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - 2000 (- \frac{1}{x})

Simplify

- 2000 (- \frac{1}{x}) : \frac{2000}{x}

= \frac{2000}{x}

Add a constant to the solution

= \frac{2000}{x} + C

x \to \infty lim (- \frac{1}{2 x})

\frac{d}{d x} (3 e^{- 7 x})

\frac{d}{d x} (\frac{10 x ^{3}}{3})

\frac{d}{d x} (\frac{x ^{2} + 1}{x + 1})

x \to \frac{x}{3} lim (sec (x))

What is the integral of-(2000)/(x^2) ?
The integral of-(2000)/(x^2) is (2000)/x+C