What is (d^2)/(dx^2)(cos^2(3pix)) ?

The answer to (d^2)/(dx^2)(cos^2(3pix)) is -18pi^2cos(6pix)

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(d^2)/(dx^2)(cos^2(3pix))

\frac{d ^{2}}{d x ^{2}} (cos^{2} (3 π x))

- 18 π^{2} cos (6 π x)

Solution steps

\frac{d ^{2}}{d x ^{2}} (cos^{2} (3 π x))

\frac{d}{d x} (cos^{2} (3 π x)) = - 6 π cos (3 π x) sin (3 π x)

= \frac{d}{d x} (- 6 π cos (3 π x) sin (3 π x))

\frac{d}{d x} (- 6 π cos (3 π x) sin (3 π x)) = - 18 π^{2} cos (6 π x)

= - 18 π^{2} cos (6 π x)

\int x^{28} e^{x^{29}} d x

\int ln (\frac{1 - x}{1 + x}) d x

\frac{d ^{2}}{d x ^{2}} (3 e^{- x^{2}})

\frac{d}{d x} (\frac{20 sin ( tw )}{tw})

y = - 5 - 8 x^{2}, (- 3, - 77)

What is (d^2)/(dx^2)(cos^2(3pix)) ?
The answer to (d^2)/(dx^2)(cos^2(3pix)) is -18pi^2cos(6pix)