What is the derivative of 8x^2+3x-2 ?

The derivative of 8x^2+3x-2 is 16x+3

What is the first derivative of 8x^2+3x-2 ?

The first derivative of 8x^2+3x-2 is 16x+3

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\frac{d}{d x} (8 x^{2} + 3 x - 2)

16 x + 3

Solution steps

\frac{d}{d x} (8 x^{2} + 3 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 16 x + 3 - 0

Simplify

= 16 x + 3

x^{3} - 3 x^{2} + 2 x, 0 \leq x \leq 2

- 3 (e^{x})^{3}

y = x^{4} - x^{2}, y = 1 - x^{2}

y^{^{''}} + y^{^{'}} - 6 y = 12 t + 10 e^{- 3 t}

\frac{d}{d θ} (θ cos (θ) - sin (θ))

What is the derivative of 8x^2+3x-2 ?
The derivative of 8x^2+3x-2 is 16x+3
What is the first derivative of 8x^2+3x-2 ?
The first derivative of 8x^2+3x-2 is 16x+3