What is the derivative of f(x)=2e^x+2ln(x) ?

The derivative of f(x)=2e^x+2ln(x) is 2e^x+2/x

What is the first derivative of f(x)=2e^x+2ln(x) ?

The first derivative of f(x)=2e^x+2ln(x) is 2e^x+2/x

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derivative of

f (x) = 2 e^{x} + 2 ln (x)

2 e^{x} + \frac{2}{x}

Solution steps

\frac{d}{d x} (2 e^{x} + 2 ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{x}) + \frac{d}{d x} (2 ln (x))

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

= 2 e^{x} + \frac{2}{x}

n = 1 \sum \infty sin (\frac{1}{n ^{2}})

\int - \frac{1}{sin ( θ )} d θ

y^{^{'}} + t^{2} y = t^{2}

\frac{d}{d x} (9 x e^{- \frac{1}{y ^{3}}})

\int \frac{1}{6 - x ^{2}} d x

What is the derivative of f(x)=2e^x+2ln(x) ?
The derivative of f(x)=2e^x+2ln(x) is 2e^x+2/x
What is the first derivative of f(x)=2e^x+2ln(x) ?
The first derivative of f(x)=2e^x+2ln(x) is 2e^x+2/x