en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+t^2y=t^2

Solution

y^{^{'}} + t^{2} y = t^{2}

Solution

y = e^{- \frac{t ^{3}}{3} + c_{1}} + 1

Solution steps

y^{'} (t) + t^{2} y = t^{2}

Solve separable ODE:

y = e^{- \frac{t ^{3}}{3} + c_{1}} + 1

y = e^{- \frac{t ^{3}}{3} + c_{1}} + 1

Popular Examples

derivative of 9xe^{-1/(y^3})

\frac{d}{d x} (9 x e^{- \frac{1}{y ^{3}}})

integral of 1/(sqrt(6-x^2))

\int \frac{1}{6 - x ^{2}} d x

derivative of 5/(7x^2)

\frac{d}{d x} (\frac{5}{7 x ^{2}})

derivative of 3x+sqrt(x)derivative of

3 x + x

(\partial)/(\partial u)((u-v)/(u+v))

\frac{\partial}{\partial u} (\frac{u - v}{u + v})

Frequently Asked Questions (FAQ)

What is the solution for y^'+t^2y=t^2 ?
The solution for y^'+t^2y=t^2 is y=e^{-(t^3)/3+c_{1}}+1