What is the solution for (d^2y)/(dt^2)+3(dy)/(dt)+2y=0 ?

The solution for (d^2y)/(dt^2)+3(dy)/(dt)+2y=0 is y=c_{1}e^{-t}+c_{2}e^{-2t}

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(d^2y)/(dt^2)+3(dy)/(dt)+2y=0

\frac{d ^{2} y}{d t ^{2}} + 3 \frac{d y}{d t} + 2 y = 0

y = c_{1} e^{- t} + c_{2} e^{- 2 t}

Solution steps

\frac{d ^{2} y}{d t ^{2}} + 3 \frac{d y}{d t} + 2 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- 2 t}

y = c_{1} e^{- t} + c_{2} e^{- 2 t}

\int (2 + tan (x))^{2} d x

f (x) = 4 sec^{2} (x)

f (x) = 5 x 1 - x^{3}

\frac{d}{d x} (\frac{7 x + 8}{4 x + 8})

\int - t e^{- 2 t} d t

What is the solution for (d^2y)/(dt^2)+3(dy)/(dt)+2y=0 ?
The solution for (d^2y)/(dt^2)+3(dy)/(dt)+2y=0 is y=c_{1}e^{-t}+c_{2}e^{-2t}