What is the derivative of (7x+8/(4x+8)) ?

The derivative of (7x+8/(4x+8)) is 3/(2(x+2)^2)

What is the first derivative of (7x+8/(4x+8)) ?

The first derivative of (7x+8/(4x+8)) is 3/(2(x+2)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{7 x + 8}{4 x + 8})

\frac{3}{2 ( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7 x + 8}{4 x + 8})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 7 x + 8 ) ( 4 x + 8 ) - \frac{d}{d x} ( 4 x + 8 ) ( 7 x + 8 )}{( 4 x + 8 ) ^{2}}

\frac{d}{d x} (7 x + 8) = 7

\frac{d}{d x} (4 x + 8) = 4

= \frac{7 ( 4 x + 8 ) - 4 ( 7 x + 8 )}{( 4 x + 8 ) ^{2}}

Simplify

\frac{7 ( 4 x + 8 ) - 4 ( 7 x + 8 )}{( 4 x + 8 ) ^{2}} : \frac{3}{2 ( x + 2 ) ^{2}}

= \frac{3}{2 ( x + 2 ) ^{2}}

\int - t e^{- 2 t} d t

t^{2} \frac{d y}{d t} + y = 0, y (5) = - 1

\int 1. 8^{(0.045 x)} - 1 d x

\int - x^{2} e^{- x} d x

(1 - x^{2}) y^{^{''}} - 2 x y^{^{'}} = 1

What is the derivative of (7x+8/(4x+8)) ?
The derivative of (7x+8/(4x+8)) is 3/(2(x+2)^2)
What is the first derivative of (7x+8/(4x+8)) ?
The first derivative of (7x+8/(4x+8)) is 3/(2(x+2)^2)