What is the integral of 1.8^{(0.045x)}-1 ?

The integral of 1.8^{(0.045x)}-1 is 37.80661…*1.02680…^x-x+C

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integral of 1.8^{(0.045x)}-1

\int 1. 8^{(0.045 x)} - 1 d x

37.80661 \dots \cdot 1.02680 \dots^{x} - x + C

Solution steps

\int 1. 8^{0.045 x} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1. 8^{0.045 x} d x - \int 1 d x

\int 1. 8^{0.045 x} d x = 37.80661 \dots \cdot 1.02680 \dots^{x}

\int 1 d x = x

= 37.80661 \dots \cdot 1.02680 \dots^{x} - x

Add a constant to the solution

= 37.80661 \dots \cdot 1.02680 \dots^{x} - x + C

\int - x^{2} e^{- x} d x

(1 - x^{2}) y^{^{''}} - 2 x y^{^{'}} = 1

x \to 0 lim (1 - 1 - x)

2 x y^{^{'}} + y = 6 x

\frac{d y}{d x} = (y - 1) (1 - 2 y)

What is the integral of 1.8^{(0.045x)}-1 ?
The integral of 1.8^{(0.045x)}-1 is 37.80661…*1.02680…^x-x+C