What is the derivative of 56x-0.02x^2 ?

The derivative of 56x-0.02x^2 is 56-0.04x

What is the first derivative of 56x-0.02x^2 ?

The first derivative of 56x-0.02x^2 is 56-0.04x

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derivative of

56 x - 0.02 x^{2}

56 - 0.04 x

Solution steps

\frac{d}{d x} (56 x - 0.02 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (56 x) - \frac{d}{d x} (0.02 x^{2})

\frac{d}{d x} (56 x) = 56

\frac{d}{d x} (0.02 x^{2}) = 0.04 x

= 56 - 0.04 x

\frac{1}{2} y^{^{''}} + 2 y = tan (2 t) - \frac{1}{2} e^{t}

\frac{\partial ^{2}}{\partial K ( b ) \partial b} (b L^{3} K (b) (b)^{2})

cos^{2} (2 π x)

sin (2 x^{2})

x^{t a n (x)}

What is the derivative of 56x-0.02x^2 ?
The derivative of 56x-0.02x^2 is 56-0.04x
What is the first derivative of 56x-0.02x^2 ?
The first derivative of 56x-0.02x^2 is 56-0.04x