What is (\partial ^2)/(\partial {K)(b)\partial b}(bL^3{K}(b)(b)^2) ?

The answer to (\partial ^2)/(\partial {K)(b)\partial b}(bL^3{K}(b)(b)^2) is 6L^3b

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(\partial ^2)/(\partial {K)(b)\partial b}(bL^3{K}(b)(b)^2)

\frac{\partial ^{3}}{\partial K ( b ) \partial b ^{2}} (b L^{3} K (b) (b)^{2})

6 L^{3} b

Solution steps

\frac{\partial ^{3}}{\partial K ( b ) \partial b ^{2}} (b L^{3} K (b) (b)^{2})

Simplify

b L^{3} K (b) (b)^{2} : L^{3} b^{3} K (b)

= \frac{\partial ^{3}}{\partial K ( b ) \partial b ^{2}} (L^{3} b^{3} K (b))

\frac{\partial}{\partial K ( b )} (L^{3} b^{3} K (b)) = L^{3} b^{3}

= \frac{\partial ^{2}}{\partial b ^{2}} (L^{3} b^{3})

\frac{\partial}{\partial b} (L^{3} b^{3}) = 3 L^{3} b^{2}

= \frac{\partial}{\partial b} (3 L^{3} b^{2})

\frac{\partial}{\partial b} (3 L^{3} b^{2}) = 6 L^{3} b

= 6 L^{3} b

cos^{2} (2 π x)

sin (2 x^{2})

x^{t a n (x)}

\frac{d}{d x} (\frac{x ^{5}}{5} - \frac{1}{2} x^{- 2})

\frac{4}{x ^{2} + 4}

What is (\partial ^2)/(\partial {K)(b)\partial b}(bL^3{K}(b)(b)^2) ?
The answer to (\partial ^2)/(\partial {K)(b)\partial b}(bL^3{K}(b)(b)^2) is 6L^3b