What is the derivative of 8/(x^2) ?

The derivative of 8/(x^2) is -(16)/(x^3)

What is the first derivative of 8/(x^2) ?

The first derivative of 8/(x^2) is -(16)/(x^3)

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derivative of

\frac{8}{x ^{2}}

- \frac{16}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{8}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 2 x^{- 2 - 1})

Simplify

8 (- 2 x^{- 2 - 1}) : - \frac{16}{x ^{3}}

= - \frac{16}{x ^{3}}

f (x) = x^{2} - 7, (5, 18)

x \to 4 lim (5 x - 2)

\int \frac{3}{x ( x ^{4} + 8 )} d x

y^{^{'}} + 9 (tan (9 x)) y = - cos (9 x)

\frac{\partial}{\partial y} (ln (x^{2} + x y))

What is the derivative of 8/(x^2) ?
The derivative of 8/(x^2) is -(16)/(x^3)
What is the first derivative of 8/(x^2) ?
The first derivative of 8/(x^2) is -(16)/(x^3)