What is the derivative of (f(x(6x))^2-4) ?

The derivative of (f(x(6x))^2-4) is 36(2x^2{f}(x) derivative of {f}(x)+2x{f}(x)^2)

What is the first derivative of (f(x(6x))^2-4) ?

The first derivative of (f(x(6x))^2-4) is 36(2x^2{f}(x) derivative of {f}(x)+2x{f}(x)^2)

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\frac{d}{d x} ((f (x) (6 x))^{2} - 4)

36 (2 x^{2} f (x) \frac{d}{d x} (f (x)) + 2 x f (x)^{2})

Solution steps

\frac{d}{d x} ((f (x) (6 x))^{2} - 4)

Simplify

(f (x) (6 x))^{2} - 4 : 36 x^{2} f (x)^{2} - 4

= \frac{d}{d x} (36 x^{2} f (x)^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (36 x^{2} f (x)^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (36 x^{2} f (x)^{2}) = 36 (2 x f (x)^{2} + 2 f (x) \frac{d}{d x} (f (x)) x^{2})

\frac{d}{d x} (4) = 0

= 36 (2 x f (x)^{2} + 2 f (x) \frac{d}{d x} (f (x)) x^{2}) - 0

Simplify

= 36 (2 x^{2} f (x) \frac{d}{d x} (f (x)) + 2 x f (x)^{2})

\frac{\partial}{\partial x} (x^{3} - 5 x^{2} y + 7 x y^{3})

\int \frac{1}{2 - e ^{- x}} d x

\frac{\partial}{\partial y} (x^{2} - x yz)

\int e^{3 x} - \frac{1}{( x + 4 ) ^{2}} d x

\int \frac{1}{x ( ln ( x ^{6} ) ) ^{8}} d x

What is the derivative of (f(x(6x))^2-4) ?
The derivative of (f(x(6x))^2-4) is 36(2x^2{f}(x) derivative of {f}(x)+2x{f}(x)^2)
What is the first derivative of (f(x(6x))^2-4) ?
The first derivative of (f(x(6x))^2-4) is 36(2x^2{f}(x) derivative of {f}(x)+2x{f}(x)^2)