What is the integral of (3x^2)/(sqrt(1-x^6)) ?

The integral of (3x^2)/(sqrt(1-x^6)) is arcsin(x^3)+C

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integral of (3x^2)/(sqrt(1-x^6))

\int \frac{3 x ^{2}}{1 - x ^{6}} d x

arcsin (x^{3}) + C

Solution steps

\int \frac{3 x ^{2}}{1 - x ^{6}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{x ^{2}}{1 - x ^{6}} d x

Apply u-substitution

: \int \frac{1}{3 1 - u ^{2}} d u

= 3 \cdot \int \frac{1}{3 1 - u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \frac{1}{3} \cdot \int \frac{1}{1 - u ^{2}} d u

Use the common integral:

\int \frac{1}{1 - u ^{2}} d u = arcsin (u)

= 3 \cdot \frac{1}{3} arcsin (u)

Substitute back

u = x^{3}

= 3 \cdot \frac{1}{3} arcsin (x^{3})

Simplify

3 \cdot \frac{1}{3} arcsin (x^{3}) : arcsin (x^{3})

= arcsin (x^{3})

Add a constant to the solution

= arcsin (x^{3}) + C

x, x^{2} - 2

x \to 0 lim (3 cos (x))

\frac{x ^{2}}{2} - 4 x + 6, \frac{x}{2} - 1, [0, 5]

s (t) = t^{3} - 5 t + 8

y = x, (1, 1)

What is the integral of (3x^2)/(sqrt(1-x^6)) ?
The integral of (3x^2)/(sqrt(1-x^6)) is arcsin(x^3)+C