What is area (x^2)/2-4x+6, x/2-1,[0,5] ?

The answer to area (x^2)/2-4x+6, x/2-1,[0,5] is 157/12

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area (x^2)/2-4x+6, x/2-1,[0,5]

area

\frac{x ^{2}}{2} - 4 x + 6, \frac{x}{2} - 1, [0, 5]

\frac{157}{12}

Decimal Notation

13.08333 \dots

Solution steps

Apply the area formula:

\int_{0}^{5} \frac{x ^{2}}{2} - 4 x + 6 - (\frac{x}{2} - 1) d x

Solve

\int_{0}^{5} \frac{x ^{2}}{2} - 4 x + 6 - (\frac{x}{2} - 1) d x : \frac{157}{12}

The area is:

= \frac{157}{12}

s (t) = t^{3} - 5 t + 8

y = x, (1, 1)

\frac{x}{x + 3}

n = 1 \sum \infty (\frac{3}{5})^{n}

\frac{d}{d t} (2 sin (t) - sin (2 t))

What is area (x^2)/2-4x+6, x/2-1,[0,5] ?
The answer to area (x^2)/2-4x+6, x/2-1,[0,5] is 157/12